(6y^3-5y)/(2y-1)

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Solution for (6y^3-5y)/(2y-1) equation:


D( y )

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0

2*y-1 = 0 // + 1

2*y = 1 // : 2

y = 1/2

y in (-oo:1/2) U (1/2:+oo)

(6*y^3-(5*y))/(2*y-1) = 0

(6*y^3-5*y)/(2*y-1) = 0

6*y^3-5*y = 0

y*(6*y^2-5) = 0

6*y^2 = 5 // : 6

y^2 = 5/6

y^2 = 5/6 // ^ 1/2

abs(y) = (5/6)^(1/2)

y = (5/6)^(1/2) or y = -(5/6)^(1/2)

y*(y-(5/6)^(1/2))*(y+(5/6)^(1/2)) = 0

(y*(y-(5/6)^(1/2))*(y+(5/6)^(1/2)))/(2*y-1) = 0

( y+(5/6)^(1/2) )

y+(5/6)^(1/2) = 0 // - (5/6)^(1/2)

y = -(5/6)^(1/2)

( y-(5/6)^(1/2) )

y-(5/6)^(1/2) = 0 // + (5/6)^(1/2)

y = (5/6)^(1/2)

( y )

y = 0

y in { -(5/6)^(1/2), (5/6)^(1/2), 0 }

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